2. Write in algebraic form as a product of disjoint permutation cycles the excision of the segment involving blocks A, B, and C of the linear chromosome below, forming a circular intermediate.
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2. Write in algebraic form as a product of disjoint permutation cycles the excision of the segment involving blocks A, B, and C of the linear chromosome below, forming a circular intermediate.
Answer:
From the image
π = ( Xh Yt ) ( Yh Ah ) ( At Bt ) ( Bh Ch ) ( Ct Zt )
Excision of the segment involving blocks A, B and C forming a circular intermediate yields:
( Xh Yt ) ( Yh Zt ) ( At Bt ) ( Bh Ch ) ( Ct Ah )
Therefore,
ρπ = ( Xh Yt ) ( Yh Zt ) ( At Bt ) ( Bh Ch ) ( Ct Ah )
ρ ( Xh Yt ) ( Yh Ah ) ( At Bt ) ( Bh Ch ) ( Ct Zt ) = ( Xh Yt ) ( Yh Zt ) ( At Bt ) ( Bh Ch ) ( Ct Ah )
ρ = (Yh Ct) (Ah Zt)
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