In an [[isotropic]] Newtonian medium the viscosity tensor \mu is highly symmetric, and the physics is considerably simplified. The strain rate tensor E can always be separated into a term E^{\mathrm{v}} that describes a rate of uniform expansion, and a term E^{\mathrm{s}} that describes the rate of pure shearing deformation, without change in volume. Likewise, the viscous stress tensor \epsilon can always be separated into an isotropic pressure component \epsilon^{\mathrm{v}} and a pure [[shearing (physics)|shearing]] stress component \epsilon^{\mathrm{s}}. If the medium is isotropic as well as Newtonian, each term of \epsilon must depend only on the corresponding term of E, by a scalar proportionality factor: \epsilon^{\mathrm{v}} = \mu^{\mathrm{v}}E^{\mathrm{v}}, and \epsilon^{\mathrm{s}} = \mu^{\mathrm{s}}E^{\mathrm{s}}, where \mu^{\mathrm{v}} and \mu^{\mathrm{s}} are real numbers. Therefore, in such media the viscosity tensor \mu has only two independent scalar parameters: a [[bulk viscosity]] coefficient \mu^{\mathrm{v}}, that defines the resitance of the medium to gradual unform compression; and a [[dynamic viscosity]] coefficent \mu^{\mathrm{s}} that expresses its resistance to gradual shearing. ---------------------------------------------------------------------- the viscous stress tensor (\varepsilon_{ij}) is related to the strain rate tensor (E_{ij}) by the(\mu_{ijk\ell}): :\varepsilon_{ij}=\sum_{k\ell}\mu_{ijk\ell}E_{k\ell} The strain rate tensor E can be broken down in a coordinate-independent ways as the sum of a scalar tensor that measures the rate of uniform expansion, and a symmetric tensor that, having zero [[trace (mathematics)|trace]], implies no change in the volume and therefore measures the rate of shear deformation: \alpha is the Attenuation is expressed in [[neper]] per meter in this equation. This remarkable law does not contain unknown or unmeasurable parameters. There has been substantial theoretical development in this field since Stokes’ pioneering work. It has brought one important correction to the Stokes law. It turns out that in addition to the [[dynamic viscosity]] the parameter of [[volume viscosity]] ηv also affects the total attenuation according to the following relationship: : \alpha = \frac{2 (\eta+\eta^v)\omega^2}{3\rho V^3} The parameter [[volume viscosity]] is surprisingly little known despite its fundamental role for [[fluid dynamics]] at high [[frequencies]]. This parameter appears in [[Navier-Stokes]] equation if it is written for [[compressible fluid]], as described in the most books on general hydrodynamics, and the acoustics,. Indeed, many rheological texts just assume the fluid to be incompressible and the volume viscosity therefore plays no role. The only values for the volume viscosity of simple Newtonian fluids known to us come from the old Litovitz and Davis review. They report a ''volume viscosity'' of water at 15 Co equals 3.09 [[centipoise]] : http://upload.wikimedia.org/wikipedia/commons/thumb/5/5d/Hookeslaw.ogg/Hookeslaw.ogg.360p.webm \epsilon_{1\,1}& \epsilon_{1\,2}& \epsilon_{1\,3}\\ \epsilon_{2\,1}& \epsilon_{2\,2}& \epsilon_{2\,3}\\ \epsilon_{3\,1}& \epsilon_{3\,2}& \epsilon_{3\,3} \sigma_{1\,1}& \sigma_{1\,2}& \sigma_{1\,3}\\ \sigma_{2\,1}& \sigma_{2\,2}& \sigma_{2\,3}\\ \sigma_{3\,1}& \sigma_{3\,2}& \sigma_{3\,3} : : F = \begin{bmatrix} F_1\\ F_2 \\ F_3 \end{bmatrix} \quad\quad\quad\quad X = \begin{bmatrix} X_1\\ X_2 \\ X_3 \end{bmatrix} Then :\kappa = \begin{bmatrix} \kappa_{1\,1}& \kappa_{1\,2}& \kappa_{1\,3}\\ \kappa_{2\,1}& \kappa_{2\,2}& \kappa_{2\,3}\\ \kappa_{3\,1}& \kappa_{3\,2}& \kappa_{3\,3} \end{bmatrix},