Determining hydration of CaCl2.xH2O

Put 20.4 g of CaCl2 hydrated in stainless steel can. Heated on electric stoveuntil stopped fizzling. Turned into 15.2 g of opaque white hard amorphous.

So the water content was 5.2 g, consistent with x = 2.1

Added EtOH to make 50.1 g (CA1).  Dissolved with difficulty to give sly cloudy white liq. Filtered:
* (CA2) clear white liq sly viscous
* (CA3) small amt of white ppt. Some dark grains (metallic?)

The white ppt (CA3) under microscope is irregular clear white grains;
maube silica? The dark grains are spherical opaque.  Could be from the cup,
which was new with strong manuf scratches on the inside.

Solubility of CaCl2 in 100 g EtOH is 25.8 g at 20 C, 35.3 g at 40 C, so interpolating should be ~30.6 g at 30 C.

Solubility of FeCl3 in 100 mL EtOH is 83 g (25 C?)

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